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#### 1260 - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 $ S(1,1) = 1 $

📌 $ S(2,1) = 1 $, $ S(2,2) = 1 $

📌 $ S(3,1) = 1 $, $ S(3,2) = 3 $, $ S(3,3) = 1 $

📌 $ S(4,3) = 6 $

📌 $ S(5,3) = 25 $

📌 $ S(6,3) = 90 $

📌 $ S(7,3) = 3 \cdot S(6,3) + S(6,2) $

📌 We compute $ S(6,2) = 2 \cdot S(5,2) + S(5,1) = 2 \cdot 15 + 1 = 31 $, or known $ S(6,2) = 31 $. Then:

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