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Home » 🔥 BIG Savings Alert: Top Food Deals Update That Will Save You HUNDREDS! - Nelissen Grade advocaten

🔥 BIG Savings Alert: Top Food Deals Update That Will Save You HUNDREDS! - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 Now, we impose the condition that species A must be analyzed before species B. In any permutation of the 5 species, for every pair A and B, A appears either before B or after B, with equal likelihood. Thus, exactly half of all permutations satisfy the condition that A comes before B.

📌 So, the number of valid sequences is:

📌 \frac{5!}{2} = \frac{120}{2} = 60

📌 \boxed{60}

📌 Question: A wildlife conservation genomics researcher is tracking 6 distinct mountain gorillas for genetic sampling. If the researcher plans to randomly select 3 gorillas to tag on Monday and the remaining 3 on Tuesday, what is the probability that two specific gorillas, Gorilla X and Gorilla Y, are both tagged on the same day?

📌 We begin by computing the total number of ways to divide 6 distinct gorillas into two groups of 3, where the order of the days (Monday and Tuesday) matters. This is simply:

📌 Now, we count the number of favorable outcomes where Gorilla X and Gorilla Y are both on the same day. There are two cases:

📌 Case 1:** Both X and Y are on Monday.

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Let $ \theta = 2z + 60^\circ $, so:
2z + 60^\circ = 30^\circ + 360^\circ k \Rightarrow 2z = -30^\circ + 36...
2z + 60^\circ = 150^\circ + 360^\circ k \Rightarrow 2z = 90^\circ + 36...
Now find all $ z \in [0^\circ, 360^\circ] $:
For $ z = -15^\circ + 180^\circ k $:
$ k = 1 $: $ 165^\circ $
$ k = 2 $: $ 345^\circ $
$ k = 0 $: $ -15^\circ $ — invalid
$ k = 3 $: $ 525^\circ $ — too large
For $ z = 45^\circ + 180^\circ k $:

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