Assign prime: 2 (for 2) × 2 (for 3 or 5) = 4, but we fix one is 2, one is odd → but in terms of outcomes, number of ways: choose which prime position is 2, other is odd → $ 2 $ positions × 2 odd choices = $ 2 \times 2 = 4 $? But we are counting assignments. - Nelissen Grade advocaten