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b² = 36. - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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First, solve the second equation for \( a \):
\[ a = 2b - 1 \]
Substitute \( a = 2b - 1 \) into the first equation:
\[ 3(2b - 1) + 4b = 12 \]
\[ 6b - 3 + 4b = 12 \]
\[ 10b - 3 = 12 \]
\[ 10b = 15 \]
\[ b = \frac{3}{2} \]
Now substitute \( b = \frac{3}{2} \) back into \( a = 2b - 1 \):
\[ a = 2\left(\frac{3}{2}\right) - 1 \]

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