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Home » \[\boxeda = \sqrt2, \, b = 1, \, c = -\frac\pi4, \, d = 3\] - Nelissen Grade advocaten

\[\boxeda = \sqrt2, \, b = 1, \, c = -\frac\pi4, \, d = 3\] - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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🔥 Popular Posts

The side length of the square is \( \sqrt{64} = 8 \) units.
The diameter of the circle is equal to the side of the square, 8 units...
The circumference of the circle is \( 2\pi \times \text{radius} = 2\pi...
Since \( 49 + 576 = 625 \), the triangle is a right triangle.
A train travels from City A to City B at 60 km/h and returns at 40 km/...
Time from A to B: \( \frac{d}{60} \) hours.
Time from B to A: \( \frac{d}{40} \) hours.
Total time is \( \frac{d}{60} + \frac{d}{40} = 5 \).
Find a common denominator: \( \frac{2d}{120} + \frac{3d}{120} = 5 \).
Combine: \( \frac{5d}{120} = 5 \).

📝 Recent Posts

Solution: To minimize
under the constraint $ x + y + z = 1 $, we apply the **Cauchy-Schwarz...
Equality occurs when $ \frac{x}{y} = \frac{y}{z} = \frac{z}{x} $, whic...
\frac{(1/3)^2}{1/3} + \frac{(1/3)^2}{1/3} + \frac{(1/3)^2}{1/3} = 3 \c...
Therefore, the minimum value is $ \boxed{1} $.
Question: Compute the sum of the roots of the equation
u\sqrt{u} - 6u + 7\sqrt{u} - 12 = 0,
given that all roots are real and non-negative.
Solution: Let $ \sqrt{u} = t $, so $ u = t^2 $. Substituting into the...
t^2 \cdot t - 6t^2 + 7t - 12 = 0 \Rightarrow t^3 - 6t^2 + 7t - 12 = 0

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