Check validity: For $ x = 2 $, $ |2 - 3| = 1 $ and $ 2(2) - 5 = -1 $. Not valid since LHS ≠ RHS. For $ x = \frac83 $, $ \left|\frac83 - 3\right| = \frac13 $ and $ 2\left(\frac83\right) - 5 = \frac13 $. Valid. - Nelissen Grade advocaten