Define $ f(a) = a + rac1a - 2 $ for $ a > 1 $. By AM-GM, $ a + rac1a \geq 2 $, with equality at $ a = 1 $. But $ a > 1 $, so $ f(a) > 0 $. However, as $ a o 1^+ $, $ f(a) o 0^+ $. The minimum value is not attained, but we seek the infimum. Since $ f(a) $ increases for $ a > 1 $, the expression approaches 0 as $ p o q^+ $, but never reaches it. However, we analyze the original expression algebraically: - Nelissen Grade advocaten