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Home » G. Clonar genes de resistencia a antibióticos - Nelissen Grade advocaten

G. Clonar genes de resistencia a antibióticos - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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## Step-by-Step Solution
我们从给定函数 $ f(x) = x - \frac{x^2}{2} $ 开始。
需要计算 $ b_3 = f(f(3)) $。
第一步：计算 $ f(3) $
代入 $ x = 3 $：
f(3) = 3 - \frac{3^2}{2} = 3 - \frac{9}{2} = 3 - 4.5 = -1.5
第二步：计算 $ f(f(3)) = f(-1.5) $
现在令 $ x = -1.5 $：
f(-1.5) = -1.5 - \frac{(-1.5)^2}{2} = -1.5 - \frac{2.25}{2} = -1.5 - 1...
因此，$ b_3 = -2.625 = -\frac{21}{8} $

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Others: 4 = $2^2$, 6 = $2\cdot3$, 10 = $2\cdot5$, 12 = $2^2\cdot3$. So...
\mathrm{lcm} = 2^3 \cdot 3^2 \cdot 5 \cdot 7 \cdot 11 = 8 \cdot 9 \cdo...
$8 \cdot 9 = 72$,
$72 \cdot 5 = 360$,
$360 \cdot 7 = 2520$,
$2520 \cdot 11 = 27720$.
So $\mathrm{lcm} = 27720$.
Now find smallest $k$ such that $27720k > 1,\!000,\!000$:
k > \frac{1,\!000,\!000}{27720} \approx 36.06.
So $k = 37$.

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