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Home » So \( \log_2(16,000) \approx 4 + 9.9657 = 13.9657 \) - Nelissen Grade advocaten

So \( \log_2(16,000) \approx 4 + 9.9657 = 13.9657 \) - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 \( \frac{7.2111}{5} \approx 1.44222 \).

📌 #### 1.44222 km/h

📌 An environmental study measures the decrease in a pollutant concentration from 150 ppm to 90 ppm over 8 months. Assuming a linear decrease, what is the monthly rate of decrease?

📌 Calculate the total decrease in concentration:

📌 \( 150 - 90 = 60 \text{ ppm} \).

📌 Determine the monthly rate of decrease:

📌 \( \frac{60 \text{ ppm}}{8 \text{ months}} = 7.5 \text{ ppm/month} \).

📌 #### 7.5 ppm/month

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