Solution: A four-digit number ranges from 1000 to 9999. A number is divisible by 5 if its last digit is 0 or 5. The smallest four-digit number divisible by 5 is 1000, and the largest is 9995. These form an arithmetic sequence with first term 1000, common difference 5, and last term 9995. The number of terms is given by \(\frac9995 - 10005 + 1 = \frac89955 + 1 = 1799 + 1 = 1800\). Therefore, there are \(\boxed1800\) four-digit numbers divisible by 5. - Nelissen Grade advocaten