Solution: Combine logs: $ \log_2\left(\fracx + 4x - 1\right) = 3 $. Rewrite in exponential form: $ \fracx + 4x - 1 = 2^3 = 8 $. Solve: $ x + 4 = 8x - 8 \Rightarrow -7x = -12 \Rightarrow x = \frac127 $. Verify $ x > 1 $ to ensure validity. - Nelissen Grade advocaten