Solution: The expression under the square root must satisfy $ 4 - x^2 \geq 0 $, so $ x \in [-2, 2] $. The maximum value of $ \sqrt4 - x^2 $ is $ 2 $ (at $ x = 0 $), and the minimum is $ 0 $ (at $ x = \pm 2 $). The range is $ \boxed[0, 2] $. - Nelissen Grade advocaten