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Home » Tiempo para la primera parte: \( \frac15050 = 3 \) horas. - Nelissen Grade advocaten

Tiempo para la primera parte: \( \frac15050 = 3 \) horas. - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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🔥 Popular Posts

### Question 10
The function \(f(x) = 3x^3 - 2x^2 + x - 5\) has a critical point at \(...
First derivative: \(f'(x) = 9x^2 - 4x + 1\)
\(f'(1) = 9(1)^2 - 4(1) + 1 = 6\) (not zero, so not a critical point,...
Second derivative: \(f''(x) = 18x - 4\)
\(f''(1) = 18(1) - 4 = 14\) (positive, indicating a local minimum if \...
Since \(f'(1)
eq 0\), \(x = 1\) is neither a maximum nor a minimum.
#### Neither
These questions and solutions cover a range of mathematical concepts i...

📝 Recent Posts

10\pi \approx 10 \times 3.14 = 31.4
The interval of interest is \( (12.56, 31.4) \). We seek the whole num...
13, 14, 15, \ldots, 31
To count them, compute:
- 13 + 1 = 19
Thus, there are \(\boxed{19}\) whole numbers in the interval.
Question:** The average of \( 2x+7 \), \( 5x-1 \), and \( 3x+4 \) is 2...
Solution:** The average of the three expressions is given by:
\frac{(2x + 7) + (5x - 1) + (3x + 4)}{3} = 24
Simplify the numerator:

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