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Home » Time for segment 3: 200 / 80 = 2.5 h - Nelissen Grade advocaten

Time for segment 3: 200 / 80 = 2.5 h - Nelissen Grade advocaten

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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📌 where \( a \) and \( b \) are the legs of the right triangle, and \( c \) is the hypotenuse. First, calculate the hypotenuse \( c \) using the Pythagorean theorem:

📌 Now, apply the formula for the radius:

📌 r = \frac{9 + 12 - 15}{2} = \frac{6}{2} = 3

📌 Thus, the radius of the inscribed circle is \(\boxed{3 \text{ cm}}\).

📌 Question:** A regular hexagon is inscribed in a circle with a radius of 10 cm. Calculate the area of the hexagon.

📌 A regular hexagon can be divided into 6 equilateral triangles. If the hexagon is inscribed in a circle, each vertex of the hexagon lies on the circle, making the radius of the circle equal to the side length of each equilateral triangle.

📌 The formula for the area \( A \) of an equilateral triangle with side length \( s \) is:

📌 A = \frac{\sqrt

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y = c \sin^2(\phi) \sin heta
z = c \sin(\phi) \cos(\phi)
Now compute \(x^2 + y^2\):
x^2 + y^2 = c^2 \sin^4(\phi) (\cos^2 heta + \sin^2 heta) = c^2 \sin^4(...
From the identity \(\sin^2(\phi) = rac{
ho^2}{c^2}\), but express \(x^2 + y^2\) in terms of \(z\):
z = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)
But use identity:
z =
ho \cos\phi = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)

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