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Home » You Won’t Believe How Many Calories Are Hidden in One Slice of Pizza! - Nelissen Grade advocaten

You Won’t Believe How Many Calories Are Hidden in One Slice of Pizza! - Nelissen Grade advocaten

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 But perhaps the problem meant: find \( m \) such that the **minimum value** is 1, which implies a different constant. Let’s suppose there is a typo and the constant is variable: \( L(w) = w^2 - 2mw + m^2 + c \). Then minimum is \( c \), and we set \( c = 1 \). But the problem fixes \( +4 \), so \( c = 4 \).

📌 Alternatively, perhaps the function is \( L(w) = w^2 - 2mw + m^2 + 4 \), and we are to find \( m \) such that the **value at vertex** is 1, but it always equals 4.

📌 Unless — wait — perhaps the loss is defined as \( L(w) = |w^2 - 2mw + m^2| + 4 \), but that’s not what is written.

📌 Alternatively, reconsider: maybe the function is \( L(w) = w^2 - 2mw + m^2 \), which has minimum 0, and 4 is additive. But then minimum is 4.

📌 Thus, unless the constant is \( m^2 + k \) and \( k = 1 \), but it’s given as 4.

📌 Only possible resolution: **the minimum loss is always 4, so no such \( m \) exists.** But that contradicts the premise.

📌 Wait — perhaps the

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